If m<ECD is six less than five times m<BCE. and m<BCD = 162°, find each measure.(Sorry bout using the wrong signs, but < is meant to represent angle)​

Answer:m∠BCE = 28° and m∠ECD = 134°Step-by-step explanation:* Lets explain how to solve the problem- The figure has three angles: ∠BCE , ∠ECD , and ∠BCD- m∠ECD is six less than five times m∠BCE- That means when we multiply measure of angle BCE by five and  then subtract six from this product the answer will be the measure  of angle ECD∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)∵ m∠BCD = m∠BCE + m∠ECD ∵ m∠BCD = 162°∴ m∠BCE + m∠ECD = 162 ⇒ (2)- Substitute equation (1) in equation (2) to replace angle ECD by   angle BCE∴ m∠BCE + (5 m∠BCE - 6) = 162- Add the like terms∴ 6 m∠BCE - 6 = 162- Add 6 to both sides∴ 6 m∠BCE = 168- Divide both sides by 6∴ m∠BCE = 28°- Substitute the measure of angle BCE in equation (1) to find the   measure of angle ECD∵ m∠ECD = 5 m∠BCE - 6∵ m∠BCE = 28°∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°* m∠BCE = 28° and m∠ECD = 134°