What is Question I (if m<EBF = 117°, fine m<ABE)​

Answer:m∠ABE = 27°Step-by-step explanation:* Lets look to the figure to solve the problem- AC is a line - Ray BF intersects the line AC at B- Ray BF ⊥ line AC ∴ ∠ABF and ∠CBF are right angles∴ m∠ABF = m∠CBF = 90°- Rays BE and BD intersect the line AC at B∵ m∠ABE = m∠DBE ⇒ have same symbol on the figure∴ BE is the bisector of angle ABD∵ m∠EBF = 117°∵ m∠EBF = m∠ABE + m∠ABF∵ m∠ABF = 90°∴ 117° = m∠ABE + 90°- Subtract 90 from both sides∴ m∠ABE = 27°